Home Chemistry

lesson 1.8 – Basic Chemical Reactions

Chemistry 1.8: Basic Chemical Reactions
Chemistry · Lesson 1.8

Basic Chemical Reactions

Reactants, Products, Conservation of Mass & Balancing Equations

01

Writing Chemical Equations

A chemical equation is a symbolic representation of a chemical reaction. It shows the reactants on the left, an arrow pointing right, and the products on the right. Coefficients (numbers in front of formulas) show the relative numbers of molecules or formula units involved.

2H₂ + O₂ 2H₂O
Reactants

Starting materials that are consumed in the reaction. Written to the left of the arrow. In the equation above, H₂ and O₂ are reactants.

Products

New substances formed by the reaction. Written to the right of the arrow. H₂O is the product in the equation above.

Coefficient

A number placed in front of a formula to indicate the relative number of molecules or formula units. The coefficient 2 before H₂ means two molecules of hydrogen.

Subscript

A number written below and to the right of an element symbol within a formula. H₂ means two hydrogen atoms per molecule. Subscripts are part of the formula — never change them when balancing.

The Golden Rule of Balancing

You may only change coefficients — numbers in front of formulas. You must never change subscripts. Changing a subscript changes the substance itself (H₂O becomes H₂O₂ — a completely different compound). Coefficients simply indicate how many molecules of each substance are involved.

02

State Symbols

Chemical equations often include state symbols in parentheses after each formula. These indicate the physical state of each substance under the reaction conditions. They are particularly important in electrochemistry and thermochemistry.

SymbolStateMeaningExample
(s)SolidSubstance is in the solid phaseNaCl(s), Fe(s), CaCO₃(s)
(l)LiquidSubstance is in the liquid phaseH₂O(l), Hg(l), Br₂(l)
(g)GasSubstance is in the gaseous phaseO₂(g), CO₂(g), HCl(g)
(aq)AqueousDissolved in water (aqueous solution)NaCl(aq), HCl(aq), NaOH(aq)
CaCO₃(s) CaO(s) + CO₂(g)
03

Why Must Equations Be Balanced?

The Law of Conservation of Mass — established by Lavoisier — states that atoms are neither created nor destroyed in a chemical reaction. They are only rearranged. This means the number of each type of atom must be the same on both sides of a chemical equation.

An unbalanced equation violates this law. Consider the unbalanced combustion of methane:

UNBALANCED CH₄ + O₂ CO₂ + H₂O
AtomLeft sideRight sideBalanced?
C11
H42
O23

Hydrogen and oxygen are unbalanced. We need to add coefficients to fix this — without touching the subscripts.

BALANCED CH₄ + 2O₂ CO₂ + 2H₂O
AtomLeft sideRight sideBalanced?
C11
H44
O44
04

The Balancing Method

There is no single rigid algorithm for balancing equations, but the following systematic approach works for most equations at this level.

1Write the unbalanced equation

Write the correct formulas for all reactants and products. Do not change any subscripts — these are fixed by the chemistry.

Fe + O₂ → Fe₂O₃
2Count atoms on each side

List every element and how many atoms of each appear on each side.

Fe: left=1, right=2 | O: left=2, right=3 — both unbalanced
3Balance the most complex molecule first

Start with the compound containing the most elements. Adjust its coefficient and recount. Here, balance Fe₂O₃ by placing a 4 in front of Fe and a 3 in front of O₂ to fix the ratio.

4Fe + 3O₂ → 2Fe₂O₃
4Verify all atoms balance

Count every atom on both sides again.

Fe: left=4 , right=4 | O: left=6 , right=6 — balanced
5Reduce coefficients if possible

Check if all coefficients share a common factor. If so, divide through to get the simplest whole-number ratio. 4, 3, 2 share no common factor — already in simplest form.

4Fe + 3O₂ → 2Fe₂O₃ ✓
Tips for Tricky Equations

Polyatomic ions (e.g. SO₄²⁻, NO₃⁻): if they appear unchanged on both sides, treat them as a single unit — count the whole ion, not individual atoms.

Odd/even trick: If you have an odd number of atoms of an element that appears in a molecule of 2 (like O₂), multiply everything by 2 first to get even numbers, then halve the coefficients at the end.

Fractions are allowed during working — just multiply through by 2 at the end to get whole numbers.

05

Reaction Types & Their Equations

Recognising the type of reaction from its equation helps you predict products and balance more efficiently. Here are the five fundamental types with representative balanced equations.

Synthesis
A + B → AB

Two or more substances combine into one. Always produces a single product.

2Mg+O₂2MgO
Decomposition
AB → A + B

One compound breaks into two or more simpler substances. Always starts with one reactant.

2H₂O2H₂+O₂
Combustion
fuel + O₂ → CO₂ + H₂O

Rapid reaction with oxygen. Complete combustion of hydrocarbons always produces CO₂ and H₂O.

C₃H₈+5O₂3CO₂+4H₂O
Single Displacement
A + BC → AC + B

One element displaces another from a compound. Requires the displacing element to be more reactive.

Zn+2HClZnCl₂+H₂
Double Displacement
AB + CD → AD + CB

Two compounds exchange ions. Often produces a precipitate (↓), a gas (↑), or water. Driving force is the removal of an ion from solution.

AgNO₃(aq)+NaCl(aq)AgCl+NaNO₃(aq)
06

Practice Balancer

Enter the correct coefficients to balance each equation. Type 1 if no coefficient is needed (coefficients of 1 are usually omitted in writing, but enter 1 here to check).

Equation 1 — Formation of water
H₂ + O₂ H₂O
Equation 2 — Combustion of ethane (C₂H₆)
C₂H₆ + O₂ CO₂ + H₂O
Equation 3 — Iron(III) oxide formation
Fe + O₂ Fe₂O₃
07

Worked Examples

Example 1Balancing by Inspection
Balance the equation: Al + HCl → AlCl₃ + H₂

Step 1 — Count atoms (unbalanced):

Al: L=1, R=1 | H: L=1, R=2 | Cl: L=1, R=3 — H and Cl unbalanced

Step 2 — Fix Cl: Need 3 Cl on left → put 3 in front of HCl.

Al + 3HCl → AlCl₃ + H₂

Step 3 — Recount H: Left=3, Right=2 — still unbalanced. Need H₂ to be 3/2 — use 3/2 H₂, then multiply through by 2.

2Al + 6HCl → 2AlCl₃ + 3H₂

Verify: Al: 2=2 ✓ | H: 6=6 ✓ | Cl: 6=6 ✓ — balanced.

Example 2Combustion Reaction
Balance the complete combustion of propane: C₃H₈ + O₂ → CO₂ + H₂O

Strategy: Balance C first, then H, then O last (O₂ is easy to adjust at the end).

Carbon: 3 C on left → need 3CO₂ on right.
C₃H₈ + O₂ → 3CO₂ + H₂O
Hydrogen: 8 H on left → need 4H₂O on right.
C₃H₈ + O₂ → 3CO₂ + 4H₂O
Oxygen: Right side has 3×2 + 4×1 = 6+4 = 10 O atoms → need 5O₂.
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Verify: C: 3=3 ✓ | H: 8=8 ✓ | O: 10=10 ✓

Example 3Identifying and Balancing
Identify the reaction type and balance: NaOH(aq) + H₂SO₄(aq) → Na₂SO₄(aq) + H₂O(l)
Reaction type: Double displacement (acid-base neutralisation). Two ionic compounds exchange partners: NaOH and H₂SO₄ swap to form Na₂SO₄ and H₂O.

Balance Na: Right side has 2 Na in Na₂SO₄ → need 2NaOH.

2NaOH + H₂SO₄ → Na₂SO₄ + H₂O

Balance H: Left has 2+2=4 H → need 2H₂O.

2NaOH(aq) + H₂SO₄(aq) → Na₂SO₄(aq) + 2H₂O(l)

Verify: Na: 2=2 ✓ | O: 2+4=6, 4+2=6 ✓ | H: 2+2=4, 4 ✓ | S: 1=1 ✓

08

Practice Questions

QuizTest your understanding

Q1. When balancing a chemical equation, you may only change:

  • A The subscripts within chemical formulas
  • B The coefficients in front of chemical formulas
  • C Both subscripts and coefficients
  • D The element symbols in the formulas

Q2. What are the correct coefficients to balance: __ N₂ + __ H₂ → __ NH₃?

  • A 1, 1, 1
  • B 1, 2, 2
  • C 1, 3, 2
  • D 2, 3, 2

Q3. The state symbol (aq) indicates that a substance is:

  • A In its liquid state
  • B Dissolved in water
  • C A gaseous product
  • D An aqueous acid only

Q4. The reaction 2KClO₃ → 2KCl + 3O₂ is classified as:

  • A Synthesis
  • B Decomposition
  • C Combustion
  • D Single displacement

Q5. How many oxygen atoms are on the right side of the balanced equation: C₄H₁₀ + 13/2 O₂ → 4CO₂ + 5H₂O? (Hint: use the whole-number equivalent: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O)

  • A 18
  • B 8
  • C 26
  • D 13
09

Key Takeaways

Lesson 1.8 Summary
  • A chemical equation shows reactants (left) and products (right) separated by an arrow. Coefficients indicate relative amounts.
  • State symbols (s), (l), (g), (aq) indicate the physical state of each substance. (aq) means dissolved in water.
  • Equations must be balanced because atoms are conserved (Law of Conservation of Mass) — the same number of each atom must appear on both sides.
  • Only coefficients may be changed when balancing — never subscripts. Changing subscripts changes the substance.
  • Balancing strategy: write unbalanced equation → count atoms → adjust coefficients starting with the most complex molecule → recount → reduce to simplest whole numbers.
  • The five reaction types: synthesis (A+B→AB), decomposition (AB→A+B), combustion (fuel+O₂→CO₂+H₂O), single displacement (A+BC→AC+B), double displacement (AB+CD→AD+CB).
  • For combustion of hydrocarbons: balance C first, then H, then O last.
← Previous Lesson
Lesson 1.7 - Atomic Mass & Number
Next Lesson →
Lesson 2.1 - Electron Configuration