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Lesson 1.7 – Atomic Mass & Number

Chemistry 1.7: Atomic Mass & Atomic Number
Chemistry · Lesson 1.7

Atomic Mass & Number

Isotopes, Relative Atomic Mass, Atomic Number & Calculations

01

Quick Review

In Lesson 1.5 we introduced the three subatomic particles and the concepts of atomic number and mass number. This lesson builds directly on those foundations, going deeper into how atomic masses are measured, what isotopes mean for real-world chemistry, and how to perform calculations using the periodic table.

Core Relationships — From Lesson 1.5
Z = protons
Atomic number — defines the element
A = protons + neutrons
Mass number — sum of heavy particles in nucleus
N = A − Z
Number of neutrons
e⁻ = Z (neutral atom)
Electrons equal protons in a neutral atom
02

Atomic Mass Units

Atoms are so small that measuring their masses in grams would produce inconveniently tiny numbers. Instead, chemists use the atomic mass unit (amu), also written as u or Da (dalton).

The atomic mass unit is defined as exactly 1/12 of the mass of a carbon-12 atom. This standard was chosen because carbon-12 is abundant, stable, and easily measured. On this scale, one proton and one neutron each have a mass of approximately 1 amu, while an electron has a mass of only 0.000549 amu — negligible for most calculations.

Atomic Mass Unit (amu)

A unit of mass equal to 1/12 the mass of one carbon-12 atom. Approximately 1.661 × 10⁻²⁷ kg. Used to express the masses of atoms and subatomic particles.

Mass Number vs Atomic Mass

Mass number (A) is always a whole number — it counts protons + neutrons. Atomic mass is a decimal value in amu — it reflects the weighted average of all isotopes.

Why electron mass is ignored

An electron has a mass of 9.109 × 10⁻³¹ kg — about 1836 times lighter than a proton. For nearly all chemistry calculations, electron mass is so small it can be ignored without meaningful error. The mass of an atom is essentially the mass of its protons and neutrons.

03

Isotopes in Depth

Most elements in nature exist as a mixture of isotopes. Each isotope has the same atomic number (same element) but a different mass number (different neutron count). The proportion of each isotope in a natural sample is called its natural abundance, expressed as a percentage.

Natural abundances are remarkably consistent — a sample of carbon from coal, diamond, human tissue, or a distant meteorite all contain approximately the same ratio of carbon-12 to carbon-13.

Natural Isotope Abundances — Selected Elements
¹H
99.98%
²H
0.02%
¹²C
98.93%
¹³C
1.07%
³⁵Cl
75.77%
³⁷Cl
24.23%
Radioactive Isotopes

Some isotopes are unstable — their nuclei contain an imbalanced ratio of protons to neutrons and decay over time, emitting radiation. These are called radioisotopes. Carbon-14 (used in radiocarbon dating), iodine-131 (used in thyroid cancer treatment), and uranium-235 (nuclear fuel) are important examples. Stable isotopes do not decay.

04

Relative Atomic Mass

Because most elements exist as mixtures of isotopes, the mass shown on the periodic table is not the mass of any single isotope — it is the relative atomic mass (also called standard atomic weight), which is the weighted average of all naturally occurring isotopes.

A weighted average gives more influence to isotopes that are more abundant. If one isotope makes up 99% of a sample, the average will be very close to its mass.

Weighted Average Atomic Mass Formula
Ar = Σ (isotope mass × fractional abundance)

Where fractional abundance = percentage ÷ 100. Sum over all naturally occurring isotopes of the element.

This is why chlorine has an atomic mass of approximately 35.5 on the periodic table — not 35 or 37. It is the weighted average of ³⁵Cl (75.77%) and ³⁷Cl (24.23%), landing between the two values but closer to 35 because it predominates.

05

Step-by-Step Calculations

Calculating weighted average atomic mass follows a consistent method. Here is the general approach broken into explicit steps.

1
Convert percentages to decimals

Divide each isotope’s percentage abundance by 100 to get its fractional abundance.

75.77% → 0.7577   |   24.23% → 0.2423
2
Multiply each isotope mass by its fractional abundance

This gives each isotope’s contribution to the average.

34.969 × 0.7577 = 26.496   |   36.966 × 0.2423 = 8.956
3
Sum all contributions

Add together the contributions from all isotopes.

26.496 + 8.956 = 35.452 amu ≈ 35.45 amu
4
Check your answer

The result should lie between the lightest and heaviest isotope masses, closer to the most abundant one. Compare to the periodic table value.

35.45 amu ✓ — matches the periodic table value for Cl
06

Using the Periodic Table for Mass Data

The periodic table gives you all the atomic number and mass data you need for calculations. Understanding what each number means — and what it doesn’t mean — prevents common errors.

Atomic Number (Z)

Always a whole number. Never changes for a given element. Use this to find protons, and (for neutral atoms) electrons. Found above the symbol in most periodic tables.

Relative Atomic Mass (Ar)

Usually a decimal. This is the weighted average — not a single isotope’s mass. Use this in mole calculations and stoichiometry. Found below the symbol in most periodic tables.

Mass Number (A)

Always a whole number. Specific to a particular isotope (e.g. ¹²C or ¹⁴C). Use this when calculating neutrons: N = A − Z. Not shown directly on periodic tables.

Neutron Number (N)

N = A − Z. Not shown on the periodic table — you always calculate it. Can vary between isotopes of the same element while Z stays constant.

Common Exam Trap

Students often confuse the relative atomic mass (decimal, periodic table value) with the mass number (whole number, specific to one isotope). You cannot calculate neutrons using the decimal atomic mass — you need the mass number of the specific isotope being described. Always identify which number is being given in a question before calculating.

07

Worked Examples

Example 1Subatomic Particles from Notation
Determine the number of protons, neutrons, and electrons for: (a) ⁵⁶Fe (neutral), (b) ⁶³Cu²⁺, (c) ³²S²⁻.
(a) ⁵⁶Fe (neutral) — Iron: Z = 26. Protons = 26. Neutrons = 56 − 26 = 30. Electrons = 26 (neutral).
(b) ⁶³Cu²⁺ — Copper: Z = 29. Protons = 29. Neutrons = 63 − 29 = 34. Electrons = 29 − 2 = 27 (lost 2, hence 2+ charge).
(c) ³²S²⁻ — Sulfide ion: Z = 16. Protons = 16. Neutrons = 32 − 16 = 16. Electrons = 16 + 2 = 18 (gained 2, hence 2− charge).
Example 2Weighted Average Atomic Mass
Boron has two naturally occurring isotopes: ¹⁰B (mass 10.013 amu, abundance 19.9%) and ¹¹B (mass 11.009 amu, abundance 80.1%). Calculate the relative atomic mass of boron.

Step 1: Convert to fractional abundances: 19.9% → 0.199; 80.1% → 0.801

Contribution of ¹⁰B = 10.013 × 0.199 = 1.9926
Contribution of ¹¹B = 11.009 × 0.801 = 8.8182
Ar = 1.9926 + 8.8182 = 10.811 amu

This matches the periodic table value for boron (10.81). The result is closer to 11 because ¹¹B is the more abundant isotope (80.1%).

Example 3Back-calculating Isotope Abundance
Gallium has two stable isotopes: ⁶⁹Ga (mass 68.926 amu) and ⁷¹Ga (mass 70.925 amu). The relative atomic mass of gallium is 69.723 amu. Calculate the percentage abundance of each isotope.

Method: Let the fractional abundance of ⁶⁹Ga = x. Then ⁷¹Ga = (1 − x). Set up the weighted average equation.

68.926x + 70.925(1 − x) = 69.723
68.926x + 70.925 − 70.925x = 69.723
−1.999x = 69.723 − 70.925 = −1.202
x = −1.202 ÷ −1.999 = 0.6013
⁶⁹Ga: 60.1%   |   ⁷¹Ga: 39.9%
08

Practice Questions

QuizTest your understanding

Q1. The relative atomic mass of an element shown on the periodic table is best described as:

  • A The mass number of the most common isotope
  • B The total number of protons and neutrons in one atom
  • C The weighted average mass of all naturally occurring isotopes
  • D The mass of one mole of atoms in grams

Q2. An atom of ⁵⁹Co (cobalt, Z = 27) has how many neutrons?

  • A 27
  • B 32
  • C 59
  • D 86

Q3. Silicon has three isotopes: ²⁸Si (92.23%), ²⁹Si (4.67%), and ³⁰Si (3.10%). Its relative atomic mass will be closest to:

  • A 29 (the middle isotope)
  • B 28 (the most abundant isotope)
  • C 30 (the heaviest isotope)
  • D Exactly 29 (the average of 28 and 30)

Q4. A ³⁴S²⁻ ion (sulfur, Z = 16) has how many electrons?

  • A 16
  • B 14
  • C 18
  • D 34

Q5. Magnesium has three isotopes with masses ~24, ~25, and ~26 amu. The periodic table lists magnesium’s atomic mass as 24.305. This tells you that:

  • A ²⁴Mg is the most abundant isotope, pulling the average close to 24
  • B ²⁶Mg is the most abundant isotope
  • C All three isotopes have equal abundance
  • D Magnesium does not have the isotope ²⁴Mg
09

Key Takeaways

Lesson 1.7 Summary
  • The atomic mass unit (amu) = 1/12 the mass of ¹²C. Protons and neutrons each have a mass of ~1 amu; electrons are negligible.
  • Atomic number (Z) = protons. Mass number (A) = protons + neutrons. Neutrons = A − Z.
  • Isotopes are atoms of the same element with different neutron counts and mass numbers but identical chemical behaviour.
  • Natural abundance is the percentage of each isotope found in a naturally occurring sample — consistent worldwide.
  • Relative atomic mass (Ar) on the periodic table is the weighted average of all naturally occurring isotopes: Ar = Σ(mass × fractional abundance).
  • The weighted average lies between isotope masses, pulled toward the most abundant isotope.
  • For ions: electrons = Z ± charge. Adding electrons (anion) makes the charge negative; removing electrons (cation) makes it positive.
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